By Ronald L. Greene Ph.D (auth.)

ISBN-10: 0387945121

ISBN-13: 9780387945125

ISBN-10: 1461242363

ISBN-13: 9781461242369

Many difficulties in classical mechanics can now be effectively solved utilizing pcs. this article integrates Maple, a general-purpose symbolic computation software, into the conventional sophomore- or junior-level mechanics direction. meant essentially as a complement to a customary textual content, it discusses the entire subject matters frequently coated within the direction and exhibits tips to resolve difficulties utilizing Maple and the way to show recommendations graphically to realize additional perception. The textual content is self-contained and will even be used for self-study or because the basic textual content in a mechanics course.

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From the Maple command > limit(f12/N12, F=Fo); we obtain the following result for part (c): JL12 :::: + e JL(ml m2) cos () . 5. Schematic of a car moving on a banked curve. , fl2 = o. Verify these expectations. 4 Car Moving Around a Banked Curve As our final example of motion in the presence of constant forces, let us consider a car of mass M moving at a constant speed v around a circular curve of radius R. The roadway is banked, making an angle e with the horizontal, as seen in the cross-sectional view shown in Fig.

4. A mass M is supported by three wires, as shown in the figure. The equations for static equilibrium are 0 T-Mg T1 sine1 + T2 sine2 - T -T1 cos81 +T2cos82 = 0 = 0 where T, T 1, and T2 are the tensions in the three wires. (a) Solve the equations simultaneously to find the tensions in the Wlres. , 81 = 82 -+ 0) the tensions T1 and T2 must be infinitely large. 5. With Maple it is often easy to verify trigonometric identities, but not so easy to find a series of commands that will transform a trigonometric expression into an equivalent one.

Two logs, each of weight W, lie in a trough with vertical walls in such a way that when viewed end-on the line between their centers makes an angle () with the horizontal. The magnitude of the forces on the bottom log due to the top log, the bottom of the trough, and one wall of the trough are F12 , FIb, and F1w , respectively. Similarly, the magnitude of the forces on the top log due to the bottom log and the other wall of the trough are F21 and F2w ' Since F21 = F12 , the equations for static equilibrium are -F12 cos () + FIw 0 FIb - W - F12 sin() 0 F12 cos () - Fzw F12 sine - W 0 0 assuming that all frictional forces are negligible.

### Classical Mechanics with Maple by Ronald L. Greene Ph.D (auth.)

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